How do we determine \(I_{illumination}\)? From what I understand it is a drift current caused by photoexcitation of electrons from the valence to the conduction band which are accelerated by the electric field in the depletion region. If we have an excitation rate \(\Gamma\) do we just say that the current is equal to that rate times the electron charge (e.g. \(I = \Gamma \cdot q_e\) )? Or is there something more subtle?
Just what you said. So it is basically something given. We won't do any real calculations of that. So like in the problem set this week we assume 50% of photons create an electron and that leads to current.
For the "PN-illuminated" video, I think that one of the two current components needs to be negative in the equation for the current through the circuit.
I believe that the illumination current has a negative sign by convention.
How do we determine \(I_{illumination}\)? From what I understand it is a drift current caused by photoexcitation of electrons from the valence to the conduction band which are accelerated by the electric field in the depletion region. If we have an excitation rate \(\Gamma\) do we just say that the current is equal to that rate times the electron charge (e.g. \(I = \Gamma \cdot q_e\) )? Or is there something more subtle?
ReplyDeleteJust what you said. So it is basically something given. We won't do any real calculations of that.
DeleteSo like in the problem set this week we assume 50% of photons create an electron and that leads to current.
Thanks for the videos!
ReplyDeleteFor the "PN-illuminated" video, I think that one of the two current components needs to be negative in the equation for the current through the circuit.
I believe that the illumination current has a negative sign by convention.