1. Using the equation we obtained for n(x) last Thursday (April 24) for an n-p junction with an applied voltage that pushes electrons to the right:
a) Calculate the diffusion current in the region \(x \ge 2d\).
b) How does the size of this current depend on the doping level of the p-type material? How does it depend on the applied voltage?
c) How does it depend on the recombination time?
d) Does our result from problem 1 for the overall magnitude (prefactor) of the current seem correct? I haven't really checked any books regarding this. Is there anything wrong with this result for the current prefactor? Does our result agree with what other people get?
There are more solutions, as well as the original problems, below the break. I think for 5 it should say "electric field". Please post any comments below.
[between 2 and 3, which problem do you think should come first?]
2. Current bottleneck problem: (I probably should have thought of asking this problem earlier (last week). I think it plays a key? role in explaining why the current through an entire n-p junction can be estimated by calculating the current at just one spot. Also, feel free to skip this and go on to the next problem if it seems confusing. I wasn't really sure what problem order would be best.)
Suppose you start with a homogeneous semiconductor doped to \(10^{17} cm^{-3}\). Suppose its dimensions are 4.5 cm x 5 mm x 5 mm, except that in the middle there is a region 5 mm long etched to 0.1 mm x 0.1 mm. Suppose you applied a voltage of 1 Volt across the long direction and just for convenience lets put the right hand side at ground.
note added: \(\tau_{tr} = 10^{-14} \, sec, \: m^* = .2\) (what does "tr" stand for?)
a) estimate the current through this semiconductor.
b) Use your estimate to calculate the voltage at each end of the narrow region. What do you get for the voltage drop across the fat sections? How does that compare with that across the narrow middle region?
c) (extra) Sketch your best guess of the current density throughout. (There is not necessarily one right answer, but this might be fun to try.)
d) Discuss transport scattering time and recombination time. To what sorts of events is each one related?
3. For somewhat complex reasons, one can approximate the total current through a biased n-p device from the value of the diffusion current at x= 2d. (We assume that at x=2d the built-in electric field associated with the junction region is zero and therefore that drift current is zero; we also assume that for \(x \ge 2d\) the decrease in this minority-carrier diffusion current is compensated by an increase in majority-carrier drift current, With these two assumptions, one can argue that that diffusion current at x=2d provides a pretty accurate estimate of the total current through the biased device.) With that in mind explain why:
a) a short recombination time might enhance this current.
b) Also explain the intriguing dependence of this current on doping \(N_a\) (on the p side) and,
c) the stunning dependence of this current on the applied voltage.
4. Consider an n-p device of dimensions 1mm x 1mm x 1cm. Each side is doped at \(10^{17} cm^{-3}\) and the energy gap is 1.5 eV. Let's assume that every recombination event leads to a photon.
a) What else would you need to know in order to be able to calculate the radiated power as a function of bias voltage? (Let's work this out here in the comments.)
b) Calculate the radiated power at 0.5, 1.0, 1.3 and 1.4 Volts (bias). (Make a table.)
note added: \(D_n = 100 \, cm^2/sec\), \(\tau_r = 10^{-14}\), and use the D_2 and D_3 (density of states) same as in last week's HW.
5. Consider an unbiased n-p device just like the one in the previous problem (but unbiased).
a) Suppose a photon excites an electron from the valence band to the conduction band. What happens to the electron? What happens to the empty state it leaves behind?
b) Suppose you connect the n and p ends with a wire of negligible resistance. How much current flow could you get through the wire if there were \(10^{18}\) photons per second exciting electrons from the VB to the CB?
c) what kind of current is that? Which way does it go?
d) extra credit: what constitutes negligible resistance in this context?
6. Suppose that the resistance is R, and maybe it is not completely negligible. How would that effect things? (Things like voltage and current.)
a) Can you think of the current as having two parts? One associated with the excitations from incident photons and another due to a voltage across the resistor (which creates a voltage across the junction that was not there before). Do those add or do they oppose each other? What you say about the nature of each current (drift or diffusion)? [I think that in E&M there is a superposition principle, associated with linearity, that is helpful here.]
b) Is this really the best way to look at (parse) the current? I am really not sure.
7. [This problem is exploratory. I am not really sure how it will work out or what it will show.] It may be of interest to explore how long it takes for a photo-excited electron to get out of the junction region.
a) For example, suppose it starts at t=0 right at the interface. Which side would it go to and how long would it take to get there? (What other input parameter(s) might one need to calculate this?)
b) Based on that, roughly how much does the illumination (as in problem 5) effect the carrier density in the interface region? How about in the other regions? Let's use \(\tau_{r} = 10^{-13} \, sec\) (this is the recombination time) for this problem, or perhaps you have a different suggestion?).
8. (added April 29) Draw a picture of a field effect transistor (FET). Any FET. Your choice. Pay some attention to the nature and details of the source and drain contact regions.
This comment has been removed by the author.
ReplyDeleteI looked up stuff in forward and reverse bias and found this cool app for forward biasing. Here it is if anyone is interested:
ReplyDeletehttp://www.acsu.buffalo.edu/~wie/applet/students/jiawang/pn.html
Number 2a kind of looks like a number 5 from the previous homework. Don't you need the scattering time to find the current through the semiconductor?
ReplyDeleteyes, true. Should we go with 10^{-14} sec like before?
DeleteAnything else you need?
DeleteAnd can we assume the effective mass (which is m* I think) is also 0.2?
Deletegood call. let's do that.
DeleteThe bias voltage creates the current. Like we were doing in class Tuesday. It is "as a function of bias voltage".
ReplyDeleteFor 2b is it okay to assume the semiconductor is ohmic? I was thinking maybe we can use \(V = IR = I \cdot \frac{L}{\sigma A}\).
ReplyDeleteThat makes sense to me.
DeleteHere are my thoughts for 4a:
ReplyDeleteTo find power, I'm thinking you need the current and the voltage and multiply them to get the power. Voltage is given to us so we're good on that. For current, I think we use what we got in problem 3, we assume that the total current density is equal to the diffusion density current at x=2d. And so we use the equation that we got in class for diffusion density current, J(x=2d) = sqrt(D_n/tau_r) * [(n_i)^2/N_a] * exp(qV/kT). If we multiply J(x=2d) by the cross sectional area of the semiconductor, than we get the total current. Finally, multiplying this current by the voltage gives us power.
So to find the diffusion current density, we would need to know what D_n is, the recombination time and n_i (N_a is 10^17).
Now the question that comes to mind is what do we do with the energy gap?? I suspect that E_gap is involved in finding n_i.
I would not assume that the power is equal to current(I) times voltage(V). That would be an interesting thing to check, but what you are asked to calculate is the power in the emitted photons --the radiated power.
DeleteOh, I didn't read the problem carefully.
DeleteI think it might be useful to know is how many electrons per second are crossing over to the valance band.
DeleteI think "how many electrons per second are crossing over to the valance band" is kind of related to what you are supposed to figure out.
Deleten_eq depends on the gap I think. Which is 1.5 eV.
DeleteWe could use a recomb time of 10^-14 sec
Is number 2 n or p doped?
ReplyDeleteyour choice. I don't think it would matter.
Deleteyes.
DeleteSpeaking of that problem, I think I said some misleading things about that in class or in a discussion after. So ignore what I said and do what you think is correct.
ReplyDeletei don' think so.
ReplyDeleteon what kind of current you calculated
ReplyDeleteThis comment has been removed by the author.
ReplyDelete5 PM
DeleteFor problem 4b, are we supposed to use a $$D_n$$ given to us in class? Also, a hint for anyone still stuck on finding the dependency between $$n_i$$ and $$E_{gap}$$ :
ReplyDelete$$n_i^2 = np$$
100 cm^2/sec
Deletealso try slash paren notation instead of double dollar signs. That leaves the math inline.
Thank you! Yeah, I never quite figured that out... thanks again.
DeleteThis comment has been removed by the author.
DeleteThis comment has been removed by the author.
DeleteTest #3: \( Test \gamma \)
DeleteOn problem 4a how is radiated power related to the pn current?
ReplyDeleteHey Brian, nice to finally see you here! Look at the units. Power is energy per second, right? Well, current is coulombs per second, or electrons per second, depending on what you're talking about. The key thing to notice: since EVERY electron recombines and releases one photon each, can't we just say we have a photon current? Then we use \( E_g = hf \) as discussed in class. I hope I could help, hopefully not too much though haha
DeleteWhat do you mean by, "Is this the best way to look at the current?". Do you mean in terms of understanding?
ReplyDeleteor is it possibly just a cos(wt), but for a limited time. I am not sure.
ReplyDeleteThe general solution to the diff eq will be a sum of sines and cosines. Using the boundary conditions we can determine the exact solution in this case.
ReplyDeleteAlthough, to get an exact answer, I think we need a few more pieces of info:
1) the starting position of the electron within the junction region
2) the width of the junction region "d"
3) the magnitude of the electric field Em
4) The effective mass
Yes, but I think it just goes through maybe 1/4 cycle. From max displacement to when it reaches x = 0.
ReplyDelete(That is assuming a starting x between 0 and d. If it starts on the other side then it would be a bit more complicated with one time dependence to get it to d and another from d to 0.)